# Logical AND Operator in C

Best Explanation of Logical AND operator in C Programming Language. With Student Grading Program. An expression containing a logical operator returns either 0 or 1 depending upon whether the expression results in true or false. Logical operators are commonly used in decision-making in C programming.

The ‘&&’ operator returns true when both the conditions under consideration are satisfied. Otherwise, it returns false. For example, a && b returns true when both a and b are true (i.e. non-zero).

## Logical AND Operator in C Programming Language With Example

Declaring Variables in C Program, We will declare a float variable as a “percentage” to take input from the user.

```main()
{
float percentage;
}```

We have printf statements, followed by the scanf statement to accept user input.

```main()
{
float percentage;

scanf("%f",percentage);
}```

To make it more friendly, we will add a few statements using printf.

```main()
{
float percentage;

printf("Calculate Division by Percentage");
scanf("%f",&percentage);

}```

Now your program will be more user-friendly to understand the user.

### Program Logic for Student Grading Program

Let’s implement the Program Logic for Student Grading Program in C language. if the percentage >= 60, it’s the first Division.

```main()
{
float percentage;

printf("Calculate Division by Score");
scanf("%f",&percentage);

if(percentage >= 60)
printf("First Division ");
}```

Here we have used the “AND” operator. And this operator requires both conditions to be true. Please make sure that all the statements are followed by a semicolon. Next line, we will write the condition for the 3rd division. i.e. percentage greater than 40 and less than 50.

```main()
{
float percentage;

printf("Calculate Division by Score");
scanf("%f",&percentage);

if(percentage >= 60)
printf("First Division ");
}```

Now we have the final condition, i.e. less than 40. Its failed.

```main()
{
float percentage;

printf("Calculate Division by Score");
scanf("%f",&percentage);

if(percentage >= 60)
printf("First Division ");
if(percentage >= 50 && percentage <60 )
printf("Second Division ");
if(percentage >= 40 && percentage <50 )
printf("Third Division ");
if(percentage < 40)
printf("FAILED");

}```

Let’s execute the program.

##### Output :

Let’s see the output.

Calculate Division by Score

Second Division

You can watch the video over here, which explains the blog in a simple video with VFX animation.

Well, Let’s iterate through the program.  You entered the value 55, and the Computer reached the first condition. It checks whether the percentage is greater than 60 or not.

The answer is negative; hence this statement of printf is not executed. In the next line, we will check two conditions. First, it’s greater than 50; yes, that’s true. Next is less than 60, it’s also true. When we put “AND” to join the conditions, the result of both the conditions should be true, then only it is considered true.

Well, the statement “Second Division” is printed. But the program won’t stop here. Since there are a few more lines yet to be executed, It will go to the next line. Here it will check a percentage greater than 50, and the answer is true; the Next condition in the. Same “IF” statement is a percentage less than 50. The result is false. So in this “IF” statement, we have one condition as true and one condition as false. So the final result is false since we have  AND operator.

I hope you understand this part. If we have both conditions true in “IF” ‘s  && statement, then it’s completely considered true. Well, the program doesn’t stop here; it goes to the next line again. Here the condition is a percentage of less than 40. The answer is false. Now it’s the last line, the end of the function.

Well, this is how we handle multiple conditions in “if and else” using operators. There is more to be learned about IF and ELSE statements.

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